SELECT xsqk.no as [学号],xsqk.name as[姓名],xscj.score as [成绩],kc.course as[课程名];
from xsqk inner join xscj inner join kc;
on xscj.courseid=kc.courseid;
on xsqk.on=xscj.no;
where xscj.score>=80;order by xsqk.no
这句的提示是：命令中不能识别短语或关键字？哪里有问题？那些表都是在打开的数据库里。

谢谢！